2 条题解
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#include<iostream> using namespace std; int tran(int x, int s) { int sum = 0; while (x>0) { sum += x % s; x /= s; } return sum; } bool fun(int i) { return tran(i, 4) == tran(i, 8); } int main() { int l, r; cin >> l >> r; int count = 0; for (int i = l; i <= r; ++i) { if (fun(i)) { count += 1; } } cout << count << endl; return 0; } -
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JAVA AC代码: 这里先给出进制转换的模板:
import java.util.*; //穿越时空之门 public class 进制转化 { static int ans; public static int ChangeTen(String s,int k) { int ans=0; for(int i=0;i<s.length();i++) { ans=ans*k+calc(s.charAt(i)); } return ans; } private static int calc(char c) { if(c>='A') { return c-'A'+10; }else { return c-'0'; } } public static String ChangeK(int n,int k) { StringBuilder ans=new StringBuilder(""); while(n!=0) { int x=n%k; if(x<10) { ans.append((char)('0'+x)); }else { ans.append((char)('A'+x-10)); } n/=k; } return ans.reverse().toString(); } public static void main(String[] args) { //System.out.println(ChangeK(15,16)); for(int i=1;i<=2024;i++) { String s1=ChangeK(i,2); String s2=ChangeK(i,4); int sum1=0,sum2=0; for(int j=0;j<s1.length();j++) { sum1+=calc(s1.charAt(j)); } for(int j=0;j<s2.length();j++) { sum2+=calc(s2.charAt(j)); } if(sum1==sum2) ans++; } System.out.println(ans); } }题解:
import java.util.*; import java.util.StringTokenizer; import java.io.*; public class Main { public static void main(String[] args) { int l=in.nextInt();int r=in.nextInt(); int ans=0; for(int i=l;i<=r;i++){ String s1=changeK(i,4);//转成4进制 String s2=changeK(i,8);//转成8进制 int num1=0,num2=0; for(int j=0;j<s1.length();j++){ num1+=s1.charAt(j)-'0';//每一位相加 } for(int j=0;j<s2.length();j++){ num2+=s2.charAt(j)-'0';//每一位相加 } if(num1==num2) ans++;//两数相等,答案++ } out.println(ans); out.close(); } public static String changeK(int n,int k){ StringBuilder ans=new StringBuilder(); while(n>0){ int x=n%k; ans.append((char)('0'+x)); n/=k; } return ans.reverse().toString(); } static FastReader in=new FastReader(); static PrintWriter out=new PrintWriter(System.out); static class FastReader{ static BufferedReader br; static StringTokenizer st; FastReader(){ br=new BufferedReader(new InputStreamReader(System.in)); } String next() { String str=""; while(st==null||!st.hasMoreElements()) { try { str=br.readLine(); }catch(IOException e) { throw new RuntimeException(e); } st=new StringTokenizer(str); } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } double nextDouble() { return Double.parseDouble(next()); } long nextLong() { return Long.parseLong(next()); } } }
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信息
- ID
- 12
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 2
- 标签
- 递交数
- 60
- 已通过
- 39
- 上传者